Answer:
The required domain is [tex]x\ne -1[/tex]
Step-by-step explanation:
The given function is
[tex]f(x)=\frac{1-x}{x}[/tex]
We need the inverse of this function.
We first of all have to let [tex]y=f(x)[/tex].
This implies that,
[tex]y=\frac{1-x}{x}[/tex]
Next, we interchange [tex]x[/tex] and [tex]y[/tex] to obtain,
[tex]x=\frac{1-y}{y}[/tex]
We make y the subject to get,
[tex]xy=1-y[/tex]
[tex]xy+y=1[/tex]
[tex](x+1)y=1[/tex]
[tex]y=\frac{1}{1+x}[/tex]
The inverse function is
[tex]f^{-1}(x)=\frac{1}{1+x}[/tex]
The domain of this function is
[tex]x+1\ne 0[/tex]
[tex]\Rightarrow x\ne -1[/tex]
The correct answer is D