Answer:
A. 45 mph
Step-by-step explanation:
Notice that your units do not match the answers. Time in your problem is in minutes, but you need the answer in miles per HOUR. So first we convert,
1 hour = 60 minutes
[tex]10 mins \times \dfrac{1hr}{60mins}=0.167hrs\\\\2 mins \times \dfrac{1hr}{60mins}=0.033hrs\\\\8 mins \times \dfrac{1hr}{60mins}=0.133hrs[/tex]
So now we have our new given:
d₁ = 5 miles d₂=0 miles (It was not moving) d₃ = 10 miles
t₁ = 0.167 hrs t₂ = 0.033 hrs t₃ = 0.133 hrs
To get the average speed, you get the sum of distances and divided it by the sum of time:
[tex]\bar{v}=\dfrac{d_1+d_2+d_3}{t_1+t_2+t_3}\\\\\bar{v}=\dfrac{5miles+0miles+10miles}{0.167hrs+0.033hrs+0.133hrs}\\\\\bar{v}=\dfrac{15miles}{0.333hrs} = 45.05 mph[/tex]
So the answer is 45.05mph or 45 mph.