Respuesta :
let the moles of chlorine-35 is n1 and chlorine-37 is n2
now we will use the formula of average atomic mass
[tex]M = \frac{n_1M_1 + n_2M_2}{n_1 + n_2}[/tex]
here let say
[tex]\frac{n_1}{n_2} = x[/tex]
[tex]35.45 = \frac{x(35) + 37}{x + 1}[/tex]
[tex]35.45 x + 35.45 = 35x + 37[/tex]
[tex]35.45 x - 35 x = 37 - 35.45[/tex]
[tex]0.45 x = 1.55[/tex]
[tex]x = 3.44[/tex]
so here since ratio of moles of chlorine 35 and chlorine 37 is more than 1 so chlorine 35 is more in the proportion in this mixture so there is most chlorine atom consist of 18 neutrons
Answer:
chlorine-35
Explanation:
We are given that Chlorine has an average atomic mass=35.45 amu
The two naturally occurring isotopes of chlorine are chlorine -35 and chlorine -37.
We have to find which isotope most contain 18 neutrons or 20 neutrons and why.
Let
[tex]\frac{x}{y}=a[/tex]
Where x= Part of chlorine-35
y=Part of chlorine-37
Then, x=a and y=1
Average atomic mass=[tex]\frac{m_1x_1+m_2x_2}{x-1+x_2}[/tex]
Using this formula
[tex]35.45=\frac{35a+37}{a+1}[/tex]
[tex]35.45a+35.45=35a+37[/tex]
[tex]35.45a-35 a=37-35.45=1.55[/tex]
[tex]0.45 a=1.55[/tex]
[tex]a=\frac{1.55}{0.45}=3.44[/tex]
The ratio of two isotopes is 3.44 which is greater than 1.
Therefore,chlorine-35 is greater than chlorine-37 in a mixture of two isotopes.
We know that atomic number of chlorine-35 is 17.
Neutron number=35-17=18
Hence, the chlorine-35 is most which contain 18 neutrons.