Question

Sam spun a spinner that is evenly spaced and numbered from 1 to 10. When it stopped, Sam spun it again. What is the probability that the spinner stopped on a number less than 4 on the first spin and on an odd number on the second spin?
a 1/5
b 1/10
c 3/20
d 2/25

Answer 1

2/10=1/5

your answer is A

Answer 2

Answer:

C. 3/20

Step-by-step explanation:

First, we need to find the probability of a number less than 4. Notice that there are only three possible events, number 1, number 2 and number 3.

So, the probability of a number less than 4 is

$P_{<4}=\frac{3}{10}=0.30 (or \ 30\%)$

On the other hand, there are 5 odd number, which are 1, 3, 5, 7 and 9. So, the probability of getting an odd number is

$P_{odd}=\frac{5}{10}=\frac{1}{2} =0.50 (or \ 50\%)$

Therefore, the probaility of getting these outcomes in two spins is

$P=\frac{3}{10} \times \frac{1}{2}=\frac{3}{20}$

So, the right answer is C.