Question

A force of 45n is excerted on an object, resulting in an acceleration of 5m/s for the object. What will be the objects acceleration be if the force doubles?

Answer 1

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Force ∝ Acceleration , constant mass. 
Hence when force double, acceleration double = 10ms⁻¹

OR. Mathematical solving : 
F=ma
45=m(5) 
m=9

Hence when F = 90 
90=9a
a=10ms⁻¹

Answer 2

F=ma, m =F/A, 45/5 = 9kg.

A =f/m (45 x 2= 90) therefore 90/9 = 10m/s^2.