Respuesta :
Answer : The pressure of the gas would be unchanged.
Explanation : Given,
Ideal gas law : [tex]PV=nRT[/tex]
where,
P = pressure of gas
V = volume of gas
T = temperature of gas
n = moles of gas
R = Gas constant
The expression for pressure is,
[tex]P=\frac{nRT}{V}[/tex]
when the volume and temperature of gas doubled then the expression for pressure is,
[tex]P_1=\frac{nR\times 2T}{2V}=\frac{nRT}{V}=P[/tex]
From this we conclude that the [tex]P=P_1[/tex] that means pressure of the gas would be unchanged.
