Respuesta :

Answer:

[tex]a=4\\\\b=\frac{7}{27}\\\\c=11\\\\d=\frac{1}{3}[/tex]

Explanation:

Since we have given that

it is the case of equal matrix where corresponding elements must be equal,

i.e

[tex]a_{11}=b_{11},a_{12}=b_{12},a_{21}=b_{21},a_{22}=b_{22}[/tex]

So,

[tex]a_{11}=b_{11}[/tex]

[tex]\frac{5a}{3}=\frac{7a}{6}+2\\\\\frac{5a}{3}-\frac{7a}{6}=2\\\\\frac{10a-7a}{6}=2\\\\\frac{3a}{6}=2\\\\\frac{a}{2}=2\\\\a=4[/tex]

Similarly,

[tex]a_{12}=b_{12}[/tex]

[tex]\frac{7}{3b}=9\\\\7=9\times 3b\\\\7=27b\\\\\frac{7}{27}=b[/tex]

Similarly,

[tex]a_{21}=b_{21}[/tex]

[tex]\frac{2c-15}{35c}=\frac{1}{5c}\\\\2c-15=7\\\\2c=7+15=22\\\\c=\frac{22}{2}=11[/tex]

Similarly,

[tex]a_{22}=b_{22}[/tex]

[tex]\frac{5}{2d}+\frac{3}{4}=\frac{9}{4d}\\\\\frac{5}{2d}-\frac{9}{4d}=\frac{3}{4}\\\\\frac{10-9}{4d}=\frac{3}{4}\\\\\frac{1}{4d}=\frac{3}{4}\\\\d=\frac{1}{3}[/tex]

Hence we get the all the values :

[tex]a=4,b=\frac{7}{27},c=11,d=\frac{1}{3}[/tex]

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