Answer:
f(x) = 10(10)+3 = 103 when x = 10
Step-by-step explanation:
Given a function piecewise as
f(x) = 2x-4 if -3<x<10
= x^2+3, if 10<=x<13
We see from the definition of f(x) that the function has domain as (-3,13) and two sets defined from (-3,10) and [10,13).
Since 10 less than or equal to sign is there in the second function interval, we find that 10 is included in that.
Hence for finding f(10) we use the function defined for interval including 10 i.e. x^2+3
Substitute 10 for x in x^2+3
f(10) = 10^2+3
=103
Hence answer is 103
