Answer:
[tex]\frac{6}{5x^2}[/tex]
Step-by-step explanation:
[tex]\sqrt{}\frac{72x^1^6}{50x^3^6}[/tex]
Dividing the numerator and denominator by 2 gives;
[tex]\sqrt{}\frac{36x^1^6}{25x^3^6}[/tex]
[tex]\sqrt{36x^1^6}[/tex] = [tex]6x^{4}[/tex]
[tex]\sqrt{25x^3^6}[/tex] = [tex]5x^{6}[/tex]
[tex]\frac{6x^4}{5x^6}[/tex] = [tex]\frac{6}{5}[/tex] × [tex]x^{4 - 6}[/tex]
This gives [tex]\frac{6}{5}[/tex] × [tex]x^{-2}[/tex]
Which can also be written as [tex]\frac{6}{5x^2}[/tex]
The first one
simplify the inside of the square root by dividing both 72 and 50 by 2 and subtracting 36 - 16 in the exponents of x
= [tex]\sqrt{}\frac{36}{25}[/tex] × 1/[tex]x^{20}[/tex]
= [tex]\frac{6}{5}[/tex] × 1 / [tex]x^{10}[/tex] = 6 / 5[tex]x^{10}[/tex]
