Question

If f(x)=x^4-x^3+x^2 and g(x)=-x^2 where x=0 what is (f/g)(x)

Answer 1

$f(x)=x^4-x^3+x^2;\ g(x)=-x^2,\ x\neq0\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}=\dfrac{x^4-x^3+x^2}{-x^2}=\dfrac{x^2(x^2-x+1)}{-x^2}=-(x^2-x+1)=-x^2+x-1$