Answer:
Number of attendants required are 16.
10000 vehicles will take 8 hours 20 min. to enter the parking area.
Step-by-step explanation:
Attendants required to park cars for each type a lot = 2
Attendants required to park cars for 6 type a lots = 2×6 = 12
Attendants required to park cars for each type b lot = 1
Attendants required to park cars for 4 type b lot = 4×1 = 4
So, total attendants required are 12+4 = 16.
total number of roads = 3
number of lanes for 1 road = 4
number of lanes for 3 roads = 3×4 = 12
number of vehicles one lane can park = 100 /hour
number of vehicles 12 lanes can park = 12×100 = 1200/hour
So, 1200 vehicles takes parking area for 60 min.
10000 vehicles takes parking area for [tex]\frac{10000\times 60}{1200}[/tex] min.
= 500 minutes.
60 min. = 1 hour
500 min. = [tex]\frac{500}{60}[/tex] hours = 8 hours 20 min.
So, 10000 vehicles will take 8 hours 20 min. to enter the parking area.