Question

How much heat is absorbed by a 72g iron skillet when its temperature rises from 14oc to 24oc?

Answer 1

Answer

The answer to this question is 331.59 J

Explanation

As we know Specifi Heat formula that

$Q=mCpΔT$

The mass is = 72 g (72/1000 = 0.072 kg)

$ΔT = 24-14 = 10^{o}C$

$Cp for iron = 460.548 J/(kg^{o}C)$

Put the values in formula

$Q = 0.072 * 10 * 460.548$

$Q = 331.59 J$

So, absorbed heat will be 331.59 J