Respuesta :

gmany

The slope-point form of a line:

[tex]y-y_0=m(x-x_0)[/tex]

We have

[tex]m=-\dfrac{1}{4}\\\\\left(-2,\ -\dfrac{9}{2}\right)\to x=-2,\ y=-\dfrac{9}{2}[/tex]

Substitute

[tex]y-\left(-\dfrac{9}{2}\right)=-\dfrac{1}{4}(x-(-2))\\\\y+\dfrac{9}{2}=-\dfrac{1}{4}(x+2)[/tex]

The slope-intercept form:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept

Solve for y:

[tex]y+\dfrac{9}{2}=-\dfrac{1}{4}(x+2)\qquad|\text{use distributive property}\\\\y+\dfrac{9}{2}=-\dfrac{1}{4}x-\dfrac{1}{2}\qquad|\text{subtract}\ \dfrac{9}{2}\ \text{from both sides}\\\\y=-\dfrac{1}{4}x-\dfrac{10}{2}\\\\y=-\dfrac{1}{4}x-5[/tex]

Amswer: y-intercept = -5.

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