Respuesta :

6x² + 11x - 35 = (3x - 5)(2x + 7)  

=> (3x - 5)(2x + 7)/(3x - 5)  

i.e. 2x + 7...........as the 3x - 5 term cancels.  


Answer:

[tex]6x^{2} +11x-35 \div 3x-5=2x+7[/tex]

Step-by-step explanation:

The given polynomials are

[tex]6x^{2} +11x-35[/tex]

[tex]3x-5[/tex]

If we divide them by the long method, the process would be as shows the image attached.

So, by long division, the quotient between the given polynomials would be

[tex]6x^{2} +11x-35 \div 3x-5=2x+7[/tex]

We can demonstrate this by multiplying [tex](3x-5)(2x+7)[/tex]

[tex](3x-5)(2x+7)=6x^{2} +21x-10x-35=6x^{2} +11x-35[/tex]

Ver imagen jajumonac
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