Respuesta :
6x² + 11x - 35 = (3x - 5)(2x + 7)
=> (3x - 5)(2x + 7)/(3x - 5)
i.e. 2x + 7...........as the 3x - 5 term cancels.
Answer:
[tex]6x^{2} +11x-35 \div 3x-5=2x+7[/tex]
Step-by-step explanation:
The given polynomials are
[tex]6x^{2} +11x-35[/tex]
[tex]3x-5[/tex]
If we divide them by the long method, the process would be as shows the image attached.
So, by long division, the quotient between the given polynomials would be
[tex]6x^{2} +11x-35 \div 3x-5=2x+7[/tex]
We can demonstrate this by multiplying [tex](3x-5)(2x+7)[/tex]
[tex](3x-5)(2x+7)=6x^{2} +21x-10x-35=6x^{2} +11x-35[/tex]
