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how far will a freely falling object have fallen from a position of rest when its instantaneous speed is 10m/s ?

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Answer:

A freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/s, it will travel 5.102 meter.

Explanation:

 We have equation of motion, [tex]v^2=u^2+2as[/tex], where u is the initial velocity, u is the final velocity, s is the displacement and a is the acceleration.

 In this case we have final velocity = 10 m/s, initial velocity = 0 m/s, and acceleration = 9.8 [tex]m/s^2[/tex].

Substituting

   [tex]10^2=0^2+2*9.8*s\\ \\ s=5.102 meter[/tex]

A freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/s, it will travel 5.102 meter.

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