Question

Roger has a nail that is 12 centimeters long. he measures and records the length of the nail as 15 centimeters. What is the percent error in Rogers measurements?

Answer 1

Answer:  25%

Step-by-step explanation:

Given : Roger has a nail that is 12 centimeters long.

He measures and records the length of the nail as 15 centimeters.

i.e. Estimated length = 15 cm and Actual length = 12 cm

The percent error in Rogers measurements is given by :-

$\dfrac{|\text{Estimated-Actual}|}{\text{Actual}}\times100\\\\=\dfrac{|12-15|}{12}\times100\\\\=\dfrac{3}{12}\times100=25\%$

Hence, the percent error in Rogers measurements is 25%.