Question

Given the balanced equation: 2 h2(g) + o2(g) → 2 h2o(l) how many grams of h2o are formed if 9.00 mol h2(g) reacts completely with an excess of o2(g)? the molar mass of h2o is 18.0 g/mol.

Answer 1

Answer:

             162 g of H₂O

Solution:

The Balance Chemical Equation is as follow,

                                     2 H₂  +  O₂    →    2 H₂O

According to equation when,

                         2 mol of H₂ is reacted  =  36 g (2 mol) H₂O is produced

So,

     9 mol H₂ on reaction will produce  =  X g of H₂O

Solving for X,

                    X =  (9 mol × 36 g) ÷ 2 mol

                    X =  162 g of H₂O

Answer 2

The mass of H₂O formed is 162 g

Stoichiometry

From the question, we are to determine the mass of H₂O that are formed

From the given balanced chemical equation

2H₂(g) + O₂(g) → 2H₂O

This means 2 moles of H₂ reacts with 1 mole of O₂ to produced 2 moles of H₂O

Now,

If 2 moles of H₂ reacts with 1 mole of O₂ to give 2 moles of H₂O

Then,

9.00 moles of H₂ will react with excess moles of O₂ to produce 9.00 moles of H₂O

∴ The number of moles of H₂O produced is 9.00 moles

Now, for the mass of H₂O produced

Using the formula,

Mass = Number of moles × Molar mass

Then,

Mass of H₂O produced = 9.00 × 18.0

Mass of H₂O produced = 162 g

Hence, the mass of H₂O formed is 162 g

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