Question

A 0.150 kg metallic block measures 25.0 mm in length, 43.0 mm in width, and 19 .0 mm in height. what is the density of the metallic block in g/cm3?

Answer 1

Answer:

7.35 g/cm^3

Explanation:

The mass of the block is:

$m=0.150 kg=150 g$

While the sizes of the block are:

$L_1 = 25.0 mm = 2.5 cm\\L_2 = 43.0 mm = 4.3 cm\\L_3 = 19.0 mm=1.9 cm$

So the volume is

$V=2.5 cm \cdot 4.3 cm \cdot 1.9 cm =20.425 cm^3$

And now we can find the density by dividing the mass of the block by its volume:

$d=\frac{m}{V}=\frac{150 g}{20.425 cm^3}=7.35 g/cm^3$

Answer 2

The density of the metallic block is equal to 7.34 g/cm3.

Density

To calculate the density of an object, its mass and volume must be related, so that:

                                                 $d = \frac{m}{v}$

Now, transform the values ​​of the units, having:

                                          $1kg = 1000g\\1mm = 0.1 cm$

                                      $0.150kg \times 1000 = 150g$

                                       $25mm \times 0.1 = 2.5cm\\43mm \times 0.1= 4.3cm\\19mm \times 0.1 = 1.9cm$

Finally, just apply the values ​​in the density expression, having:

                                             $d = \frac{150}{2.5\times4.3\times1.9} \\d = 7.34 g/cm^{3}$

So, the density of the metallic block is equal to 7.34 g/cm3.

Learn more about density in: brainly.com/question/952755