Question

100 POINTS! NEED HELP QUICK! I'M SUPER CONFUSED!

The table shows the solubility of two substances in water at 20 °C.

Part 1: What is the difference between K and L?
Part 2: Explain your answer for Part 1.

Answer 1

the difference between k and l is that (k) is more soluble than (L) because the mass of 200 has lower grams than 100.

Answer 2

Explanation:

It is known that at $20^{o}C$ the solubility of sodium chloride per 100 grams of water is 36 grams. Whereas the solubility of lead nitrate per 100 grams of water is 54.3 grams.

Therefore, when 200 kg (or 200000 g) of sodium chloride's solubility is 36 then calculate solubility of 100 Kg, that is, 100000 g of sodium chloride as follows.

                     Solubility = $\frac{36 g}{200000 g} \times 100000 g$

                                      = 18 g

On the other hand, when 100000 g of lead nitrate's solubility is 54 then calculate solubility of 200 Kg, that is, 200000 g of lead nitrate as follows.

                     Solubility = $\frac{54 g}{100000 g} \times 200000 g$

                                      = 108 g

Hence, difference between K and L is as follows.

               Difference = solubility of K - solubility of L

                                  = 108 g - 18 g

                                   = 90 g

Thus, we can conclude that K is more soluble than L.