Respuesta :
For this case, the first thing we must do is define variables.
We have then:
x: number of classes:
y: total cost
For Devin we have the following equation:
[tex]y = 2x + 30[/tex]
For Jared we have:
[tex]y = 5x[/tex]
Then, by the time the cost of both is the same, we have:
[tex]2x + 30 = 5x[/tex]
From here, we clear the value of x.
We have then:
[tex]5x - 2x = 30[/tex]
[tex]3x = 30[/tex]
[tex]x = \frac{30}{3}[/tex]
[tex]x = 10[/tex]
Answer:
it takes 10 classes for Devin's total cost to equal Jared's total cost
Answer:
10
Step-by-step explanation:
Let x be the number of classes Devin and Jared takes. The total cost of Devin will be:
[tex]=30+2\codt{x}[/tex]
The total cost of Jared will be:
[tex]5\cdot{x}[/tex]
The totals must equal to each other:
[tex]30+2\codt{x}=5\cdot{x}[/tex]
We can solve x:
[tex]30=3\cdot{x}[/tex]
[tex]10=x[/tex]
It would take 10 classes