Question

. A student adds 50 mL of Lead (II) Nitrate solution to 50 mL of potassium iodide. Each
solution is colorless, but when these two liquids are mixed, a yellow precipitate is
observed. What has most likely happened in the experiment?

Answer 1

Answer:

after the reaction between Lead (II) Nitrate solution and potassium iodide occur Lead(II) iodide  was formed and it's yellow color.

Explanation:

Pb(NO3)2 + KI = KNO3 + PbI2