Question

Aqueous iron(iii) chloride reacts with solid magnesium to form aqueous magnesium chloride and solid iron . write a balanced chemical equation for this reaction.

Answer 1

Answer:

            2 FeCl₃ + 3 Mg    →     3 MgCl₂ + 2 Fe

Explanation:

Chemical Formula of given substances are as follow,

Iron (III) Chloride  =  FeCl₃

Magnesium  =  Mg

Magnesium Chloride  =  MgCl₂

Iron  =  Fe

Step 1: Write imbalance chemical equation;

                                  FeCl₃ +  Mg    →    MgCl₂ +  Fe

Step 2: Balance Chlorine atoms as;

                                 2 FeCl₃ +  Mg    →   3 MgCl₂ +  Fe

Step 3: Balance Fe and Mg respectively;

                                2 FeCl₃ + 3 Mg    →   3 MgCl₂ +  2 Fe

Answer 2

The balanced chemical equation for the reaction of aqueous iron(iii) chloride with solid magnesium to form aqueous magnesium chloride and solid iron is:

2FeCl₃(aq) + 3Mg(s) —> 3MgCl₂(aq) + 2Fe(s)

The equation for the reaction of aqueous iron(iii) chloride with solid magnesium to form aqueous magnesium chloride and solid iron can written as follow:

Iron(iii) chloride => FeCl₃

Magnesium => Mg

Magnesium chloride => MgCl₂

Iron => Fe

Iron(iii) chloride + Magnesium —> Magnesium chloride + Iron

FeCl₃(aq) + Mg(s) —> MgCl₂(aq) + Fe(s)

The above equation can be balance as illustrated:

FeCl₃(aq) + Mg(s) —> MgCl₂(aq) + Fe(s)

• There are 3 atoms of Cl on the left side and 2 atoms on right side. It can be balance by writing 2 before FeCl₃ and 3 before MgCl₂ as shown below:

2FeCl₃(aq) + Mg(s) —> 3MgCl₂(aq) + Fe(s)

• There are 2 atoms of Fe on the left side and 1 atom on the right side. It can be balance by writing 2 before Fe as shown below:

2FeCl₃(aq) + Mg(s) —> 3MgCl₂(aq) + 2Fe(s)

• There are 3 atoms of Mg on the right side and 1 atom on the left side. It can be balance by writing 3 before Mg as shown below:

2FeCl₃(aq) + 3Mg(s) —> 3MgCl₂(aq) + 2Fe(s)

Thus, the equation is balanced.

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