Question

Calculate the specific heat of glass if 13.4 J of energy are required to heat 8.0 g of water by 2.0°C.

Answer 1

Answer:- Specific heat of glass is $c=0.84\frac{J}{g.^0C}$ .

Solution:- It asks to calculate the specific heat of glass when 13.4 J of heat is required to heat 8.0 g of water by 2.0 degree C.

The equation used for solving this type of problems is:

$q=mc\Delta T$

where, q is the heat energy, m is the mass, c is specific heat and $\Delta T$ is change in temperature.

From given info:

q = 13.4 J

m = 8.0 g

$\Delta T$ = 2.0 degree C

c = ?

Let's plug in the values in the equation and solve it for c:

$13.4J=8.0g*c*2.0 ^0C$

On rearrangement:

$c=\frac{13.4J}{8.0g*2.0^0C}$

$c=0.84\frac{J}{g.^0C}$

So, the specific heat of glass is $c=0.84\frac{J}{g.^0C}$ .