Question

How many moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa)?

Answer 1

PV=vRT
P-preassure
V -volume
v-moles
R -const
T-temp

v=PV/RT=0,98*6,8/0,082*293=

i transformed kPascals into pascals and then into atm

100kpa=0,98atm