Respuesta :

[tex] \bf v=-4i-j\implies v=\stackrel{a}{-4}i\stackrel{b}{-1}j\qquad tan(\theta )=\cfrac{b}{a}\implies tan(\theta )=\cfrac{-1}{-4}
\\\\\\
tan(\theta )=\cfrac{1}{4}\implies \measuredangle \theta =tan^{-1}\left( \cfrac{1}{4} \right)\implies \measuredangle \theta \approx
\begin{cases}
0.2449787~radians\\
14.03624^o
\end{cases} [/tex]

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