Respuesta :

Ishankahps
Answer : 5.16 mol

Explanation : 
I think that the question should be "How many moles of fluorine are contained in 115.6 L at STP?"

Let's assume that the gas is an ideal gas.

1 mole of ideal gas has the volume as 22.4 L at STP (273 K , 1 atm)

The given volume is 115.6 L. 

moles in 22.4 L of gas = 1 mol
moles in 115.6 L of gas = (1 mol x 115.6 L) / 22.4 L

                                      = 5.16 mol

Answer: 5.16

Explanation:

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