Let's assume
base is b
height is h
we are given
[tex] \frac{b}{h} =\frac{4}{3} [/tex]
now, we can solve for b
[tex] b =\frac{4}{3}h [/tex]
we know that area of any triangle is
[tex] A =\frac{1}{2}*b*h [/tex]
we can plug b
[tex] A =\frac{1}{2}*(\frac{4}{3}h)*h [/tex]
we are given
A=150
[tex] 150 =\frac{1}{2}*(\frac{4}{3}h)*h [/tex]
now, we can solve for h
so, we get
[tex] h =15mm [/tex].............Answer