Respuesta :
[tex] {\text{In triangle XYZ}},{\text{ square of one side is equal to the sum of squares of other two sides, }} \hfill \\
{\text{,i}}{\text{.e}}{\text{., if triangle XYZ has sides of measure }}x\,{\text{unit, }}y\,{\text{unit and }}z\,{\text{unit}} \hfill \\
{\text{opposite to the corresponding vertices }}X,{\text{ }}Y\,{\text{and }}Z\,{\text{respectively, then}} \hfill \\
{z^2} = {x^2} + {y^2} \hfill \\
{\text{Since, the given triangle satisfying the condition of Pythagoras theorem, }} \hfill \\
{\text{thus, the given triangle would be a right angled triangle and thereby the measure}} \hfill \\
{\text{of one angle of triangle will be a right angle say at vertex Z}}{\text{.}} \hfill \\
\Rightarrow m\left( {\angle Z} \right) = 90^\circ \hfill \\
\Rightarrow m\left( {\angle XZY} \right) = 90^\circ \hfill \\
{\text{Thus,the measure of angle XZY is equal to }}90{\text{ }}degrees. \hfill \\
[/tex]

Answer:
Measurement of XZY=90 degrees!
Step-by-step explanation:
I got it correct on my test :)