Question

What is the (OH-) in a solution with a pOH of 6.48

Answer 1

Through manipulation of equations, we are able to obtain the equation:

$-pOH= log [ OH^{-}]$

Then we can transform the equation into:

$[ OH^{-}]= 10^{-pOH}$

Then we are able to plug in the pOH and directly get [OH-]:

$[ OH^{-}] = 10^{-6.48}$

$[ OH^{-}]=3.31* 10^{-7} M$

Answer 2

The pOH value of the given solution is 6.48, the [OH⁻¹] concentration in the solution is 3.37×10⁻⁷.

What is the pOH value?

pOH value is a negative log value of  [OH⁻¹] concentration in a solution, a measure of [OH⁻¹]ion concentration of a solution

pOH can also be calculated by 14 – pH, now convert value of 6.48 back into its concentration    

-pOH= log  [OH⁻¹]

 [OH⁻¹] =log⁻⁶°⁴⁸            

        = 3.37 × 10⁻⁷  

Convert the value in its respective given log value and simplify it, the ×  sign gets converted into + in the solution.

                                                         

Hence, the concentration of the given solution is 3.37×10⁻⁷

Learn more about pH.

https://brainly.in/question/1201953

#SPJ2