Question

The function g(x) = x^3 has the point (-3, -27) on its graph. The function g(x) is:

even
odd

Answer 1

Answer:

Odd.

Step-by-step explanation:

You don't need the point, its pretty much useless.

If its even, when you plug -x into the equation, it will stay the same

If its odd, when you plug -x into the equation, the signs will change

g(x) = $x^{3}$    

Lets plug in -x.

g(x) = (-x)³

g(x) = -x³

The equation is different! That means the equation is odd!