[tex]NH _{4} ^{+} + H_{2} O \ \textless \ ----\ \textgreater \ NH _{3} + H_{3}O ^{+}
[/tex]Answer : - While dissolving nitrate in water the pH of water becomes slightly acidic. The reaction is explained below :
At the first stage ammonium nitrate is dissolved in water:-
[tex]NH _{4} NO_{3} + H_{2} O ----\ \textgreater \ NH_{4} ^{+} + NO_{3} ^{-} [/tex]
In the later stage when excess of ammonium ions are produced in water then these ions react with water again producing acidic hydronium ions.
A reversible reaction occurs at this stage.
[tex]NH _{4} ^{+} + H_{2} O \ \textless \ ----\ \textgreater \ NH _{3} + H_{3}O ^{+}
[/tex]
So the net ionic equation for this reaction will be :-
[tex]NH _{4} ^{+} + H_{2} O ----\ \textgreater \ NH _{3} + H_{3}O ^{+}[/tex]