Question

PLEASE ANSWER I NEED DONE
In the figure, OA = r and OC = R. The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the outer circle to the area of the sector removed from the inner circle is .

R^2/r^2
R/r
(R^2 - r^2)/r^2
1

Answer 1

the picture in the attached figure

we know that
area of a sector=(∅/2)*r²--------> when ∅ is in radians

area of sector inner circle=(∅/2)*r²

area of sector outer circle=(∅/2)*R²-(∅/2)*r²

The ratio of the area of the sector removed from the outer circle to the area of the sector removed from the inner circle is
[(∅/2)*R²-(∅/2)*r²]/[(∅/2)*r²]-----> [R²-r²]/[r²]

therefore

the answer is
(R^2 - r^2)/r^2

Answer 2

Answer:

The other answer is wrong.  It is r^2/R^2.

Step-by-step explanation: