Question

the point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y 7 = -2/5 (x – 10). what is the standard form of the equation for this line? 2x – 5y = –15 2x – 5y = –17 2x 5y = –15 2x 5y = –17

Answer 1

Gradient, m=$\frac{-1--7}{-5-10}$
m=$\frac{6}{-15} = \frac{-2}{5}$
Standard form then is;
y=$\frac{-2}{5} x+c$

Finding value of c using point (-5,-1);
-1=$\frac{-2}{5} *(-5)$+c
-1=2+c
c=-3
y=$\frac{-2}{5} x-3$