Respuesta :

Answer:

The value of the Rational expression when [tex]x=-2[/tex] is: [tex]-7[/tex]

Step-by-step explanation:

For this exercise is important to remember:

  • When a negative number is raised to an even power, the result will be positive.
  • The multiplication of signs:

       [tex](+)(+)=+\\(-)(-)=+\\(-)(+)=-[/tex]

Then, given the following Rational expression:

[tex]\frac{2x^2+5x+9}{x^2+2x-1}[/tex]

You need to follow these steps in order to find its value when [tex]x=-2[/tex]:

1. Substitute the given value of "x" ([tex]x=2[/tex]) into the expression:

 [tex]\frac{2(-2)^2+5(-2)+9}{(-2)^2+2(-2)-1}[/tex]

2. Evaluate and simplify:

[tex]\frac{2(4)+5(-2)+9}{4+2(-2)-1}=\frac{8-10+9}{4-4-1}=\frac{7}{-1}=-7[/tex]

Answer: -7

Step-by-step explanation:

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