Question

what are the zeros of the polynomial x2+4x-12

Answer 1

Hi,
$x^2+4x-12=0\\ \Rightarrow\ x^2+6x-2x-12=)0\\ \Rightarrow\ x(x+6)-2(x+6)=0\\ \Rightarrow\ (x+6)(x-2)=0\\ \boxed{\Rightarrow\ x=-6\ or\ x=2}$