First, we are going to draw a diagram of the situation.
Next, from triangle ABC we can find the length of [tex]a[/tex] using the sine trig function:
[tex]sin( \alpha )= \frac{opposite.side}{hypotenuse} [/tex]
[tex]sin(42)= \frac{2440}{h} [/tex]
[tex]h= \frac{2440}{sin(42)} [/tex]
[tex]h=3646.52[/tex]
Now, since we know that the angle between the lines of sight to the landmarks is 68°, we can use the law of sines in triangle ABD to find the distance [tex]a[/tex] between the two landmarks:
[tex] \frac{a}{sin(68)} = \frac{3646.52}{sin(37} [/tex]
[tex]a= \frac{3646.52sin(68)}{sin(37)} [/tex]
[tex]a=5617.996[/tex]
We can conclude that the distance between the two landmarks is 5618 feet.