Question

Find the 37th term of the sequence 2, 5, 8, 11, 14, . . .

Answer 1

Answer: 110

Use the formula $a_n=a_1+d(n-1)$

The sequence is $a_n=3n-1$

Simply plug in 37 into the formula and you get 110.

Hope this helps!!!

$Sofia$

Answer 2

The 37th term of the sequence is 110.

What is an arithmetic sequence?

An arithmetic sequence is defined as an arrangement of numbers which is a particular order.

The formula to find the general term of an arithmetic sequence is,

Tₙ = a₁ + (n-1)d

In arithmetic, sequence d represents the common difference.

Where aₙ is the nth term of the sequence and a₁ is the first term.

Given that the sequence as 2, 5, 8, 11, 14, . . .

Here the first term is 2.

a₁ = 2

So, the common difference = 5 - 2 = 3

d = 3

To determine the 37th term of the sequence

Tₙ = a₁ + (n-1)d

Substitute the values of n = 37, a₁ = 2, and d = 3 in the formula of  arithmetic sequence

T₃₇ = 2 + (37-1)3

T₃₇ = 2 + (36)3

T₃₇ = 2 + 108

T₃₇ = 110

Hence, the 37th term of the sequence is 110.

Learn more about arithmetic sequence here:

brainly.com/question/21961097

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