Respuesta :
The radius of the circle is given to be r = 14.5
Let the center be O. So OB is the radius = 14.5
We can draw a triangle as shown in the image below. We have a right angled triangle. We know the hypotenuse and the base, we need to find the perpendicular side. This can be done using the Pythagorean theorem.
So, we can write:
[tex](14.5)^{2}=10^{2}+OA^{2} \\ \\ OA^{2}=110.25 \\ \\ OA=10.5 [/tex]
Thus, the measure of OA = 10.5
OB = OA + AB
14.5 = 10.5 + AB
⇒
AB = 4
Let the center be O. So OB is the radius = 14.5
We can draw a triangle as shown in the image below. We have a right angled triangle. We know the hypotenuse and the base, we need to find the perpendicular side. This can be done using the Pythagorean theorem.
So, we can write:
[tex](14.5)^{2}=10^{2}+OA^{2} \\ \\ OA^{2}=110.25 \\ \\ OA=10.5 [/tex]
Thus, the measure of OA = 10.5
OB = OA + AB
14.5 = 10.5 + AB
⇒
AB = 4
r = 14.5
form a right triangle with the 10 as 1st side and r as the hypotenuse.
get the length of the other side using pythagorean.
c = sqrt(14.5^2 - 10^2) = 10.5
The length from the center to point A = c = 10.5
AB = r - c = 14.5 - 10.5 = 4
length AB = 4
form a right triangle with the 10 as 1st side and r as the hypotenuse.
get the length of the other side using pythagorean.
c = sqrt(14.5^2 - 10^2) = 10.5
The length from the center to point A = c = 10.5
AB = r - c = 14.5 - 10.5 = 4
length AB = 4