Question

What is the value of q when the solution contains 2.50×x10−3 m mg2+ and 2.00×10−3m co32−?

Answer 1

The correct answer is: Q = $5.0 * 10^{-6}$

Explanation:

The chemical equation is:
$MgCO_3 \to Mg^{2+} + CO_3^{2-}$

The value of Q can be obtained as follows:

Q = [$Mg^{2+}$][$CO_3^{2-}$]
Q = [2.50×x10^−3][2.00×10^−3]
Q = $5.0 * 10^{-6}$