Let's assume that CO₂ has ideal gas behavior.
Then we can use ideal gas formula to solve this.
PV = nRT
Where,
P = Pressure of the gas (Pa)
V = Volume of the gas (m³)
n = moles of the gas (mol)
R = Universal gas constant (8.314 J K⁻¹ mol⁻¹)
T = Temperature in Kelvin (K)
In this problem,
P = Standard pressure = 1 atm = 101325 Pa
V = 43 L = 43 x 10⁻³ m³
R = 8.314 J K⁻¹ mol⁻¹
T = standard temperature = 273 K
n = ?
PV = nRT
By rearranging,
n = PV / RT
n = (101325 Pa x 43 x 10⁻³ m³) / (8.314 J K⁻¹ mol⁻¹ x 273 K)
n = 1.92 mol
Hence moles of CO₂ gas in 43 L at STP = 1.92 mol
