Question

what is the volume of 12.0 g of cl2 gas at stp

Answer 1

Hi I think I might know the answer to your question it is pretty tricky though!
Chlorine Gas = 70.8 grams/moles
Moles of Chlorine Gas = 57.8/70.8 = 0.816 mol
Volume Gas at STP = 22.4 L/mol
Volume of Chlorine Gas = .816*22.4=18.22 Litters
I hoped that helps if not so sorry!

Answer 2

Answer:

$V=3.79L$

Explanation:

Hello,

In this case, we are talking about an ideal gas problem in which 12.0 g of chlorine gas is at standard both pressure (1atm) and temperature (0°C), therefore, to compute the corresponding volume, one applies the ideal gas law, then converts from grams to moles considering the diatomic chlorine and subsequently solves for volume as shown below:

$PV=nRT\\V=\frac{nRT}{P}=\frac{12.0gCl_2*\frac{1molCl_2}{70.9gCl_2} *0.082 \frac{atm*L}{mol*K} * 273.15K}{1atm}  \\V=3.79L$

Best regards.