Question

plz help and explain thanks

Answer 1

$\dfrac{x^0}{q^{-3}} = \dfrac{5^0}{(-6)^{-3}}= \dfrac{1}{(-6)^{-3}} = (-6)^3 = -216$

Answer 2

hey there!:


for q = - 6 and x = 5 :

   5⁰
------
(-6)⁻³ 


Apply rule :  a⁰ = 1  , a≠0

5⁰ = 1     :    

    1
* -------
   (-6)⁻³


Apply exponent rule:  (-a)ⁿ = - aⁿ  , if  " n " is  odd :

(-6)⁻³   = -6⁻³


     1
* -------
   -6⁻³


Apply fraction rule : a/-b  = - a/b


= - 1 /  -6⁻³

Apply exponent rule: a⁻ᵇ =  1 / ab


6⁻³ = 1 / 6³

=> ( - 1/1 ) / ( 6³ )

= - 6³ / 1

Apply rule a/1  = a

= - 6³

* 6 * 6 * 6 => 216

a = -216

hope this helps!