Respuesta :
[tex] |\Omega|=52\\
|A|=\underbrace{26}_{\text{red}}+\underbrace{4}_{\text{king}}-\underbrace{2}_{\text{red king}}=28\\\\
P(A)=\dfrac{28}{52}=\dfrac{7}{13}\approx54\% [/tex]
[tex] |\Omega|=52\\
|A|=\underbrace{26}_{\text{red}}+\underbrace{4}_{\text{king}}-\underbrace{2}_{\text{red king}}=28\\\\
P(A)=\dfrac{28}{52}=\dfrac{7}{13}\approx54\% [/tex]