Respuesta :
This is an approximately bell-shaped distribution. The highest bar is in the center, with height = 12. Just to its left and right are bars of heights 6 and 5. At the extremes are bars of heights 2 and 1.
If the highest bar was on the left, it would be skewed left (and if it was on the right, skewed right). A uniform distribution would more or less have the same height level over all the bars.
If the highest bar was on the left, it would be skewed left (and if it was on the right, skewed right). A uniform distribution would more or less have the same height level over all the bars.
Answer with explanation:
The Description about the Histogram is
Vertical Axis = 0-14
Horizontal Axis Bar Height
0-49 2
50-99 6
100-149 12
150-199 5
200-249 1
Plotting the Histogram
→Class interval 150-199 has frequency =5, and class interval 50-99, has frequency equal to 6.
→The curve is not uniform on both sides.
→The interval in which mean , median lies has 6+2=8 frequency on the left of that interval , and 5+1=6, values on the right of class interval [100-149].We can conclude that,the histogram is left Skewed.
→But when we join ,mid points of histogram,the curve obtained resembles with a normal distribution curve called bell curve.It is not exactly bell shaped,as not uniform on both sides explained above.
Option C: Approximately bell Shaped