koolgirl815 koolgirl815

03-05-2018
Chemistry

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If 1495 J of heat is needed to raise the temperature of a 319 g sample of a metal from 55.0°C to 66.0°C, what is the specific heat capacity of the metal?

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kenmyna kenmyna

13-05-2018

The specific heat capacity of the metal is calculated using the following formula
Q(heat)= MC delta T
Q= 1495 j
c= specific heat capacity =?
M(mass)=319 g
delta T = change in temperature = 66-55 =11 c
by making c the subject of the formula

C=Q /M delta T
c= 1495 j/ 319 g x 11 c =0.426 j/g/c

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