Respuesta :
If the image that accompanies this problem is the same as that in my attachment, then the area of the new circle is:
Given data in the attachment:GY = 10 cmYX = 16 cm
A = πr²A = π (26cm)²A = 676cm² π
Given data in the attachment:GY = 10 cmYX = 16 cm
A = πr²A = π (26cm)²A = 676cm² π