Respuesta :
we can use the following dilution equation
c1v1 = c2v2
where c1 is concentration and v1 is the volume of the concentrated solution
c2 is concentration and v2 is final volume of the diluted solution
substituting the values
6.00 M x 175 mL = 2.00 M x V
V = 525 mL
final volume of the diluted solution is 525 mL
since there's already 175 mL of acid ,
volume of water to be added - 525 - 175 = 350 mL
350 mL of water should be added
c1v1 = c2v2
where c1 is concentration and v1 is the volume of the concentrated solution
c2 is concentration and v2 is final volume of the diluted solution
substituting the values
6.00 M x 175 mL = 2.00 M x V
V = 525 mL
final volume of the diluted solution is 525 mL
since there's already 175 mL of acid ,
volume of water to be added - 525 - 175 = 350 mL
350 mL of water should be added
Answer:
350 mL
Explanation:
Given:
concentration of stock solution of HCl =6.00 M
Volume of stock solution of HCl = 175 mL
concentration of required solution = 2.00 M
total volume of required solution = to be determined
This is problem of dilution. We have to determine the total volume of required solution to be made, from the given stock solution.
We will use
M₁V₁=M₂V₂
Where
M₁=concentration of stock solution
V₁= volume of stock solution
M₂=concentration of required solution
V₂=volume of required solution
Putting values
6X175=2XV₂
V₂=525 mL
so total volume of required solution formed will be 525 mL
We have already 175 mL of solution in it. The water need is difference of these two volume.
water added = 525-175= 350 mL
