Question

Triangle ABC has vertices A(–2, –3), B(–5, –3), and C(–4, –2). The triangle is rotated 90° counterclockwise around the origin.


What is the correct set of image points for triangle A’B’C’?
A’(3, 2), B’(3, 5), C’(2, 4)
→→A’(3, –2), B’(3, –5), C’(2, –4)←←
A’(–3, –2), B’(–3, –5), C’(–2, –4)
A’(–3, 2), B’(–3, 5), C’(–2, 4)

Answer is B :)

Answer 1

The answer is the option B: A'(3, -2), B'(3, -5), C'(2, -4).

The explanation is shown below:

1. You must apply  the following rule of rotation when the figure is rotated 90° counterclockwise around the origin:

$(x,y)$→$(-y,x)$

2. Then, as you can see, you must switch $x$ and $y$ and multiply $y$ by -1.

3. Keeping this on mind, you have that the vertices of the triangle A'B'C' are the following:

A(-2,-3)→A'(3,-2)

B(-5,-3)→B'(3,-5)

C(-4,-2)→C(2,-4)

4. Therefore, you can conclude that the answer is the option B.

Answer 2

Answer:B

Step-by-step explanation:B