Question

evaluate a = log(0.1) and b = ln(e^3)

Answer 1

$log0.1=log\dfrac{1}{10}=log10^{-1}=-log10=-1\to a=-1\\\\lne^3=3lne=3\to b=3\\\\Used:\\\\a^{-1}=\dfrac{1}{a}\\\ loga^b=b\cdot loga\\\\log_aa=1$