Answer:
The area of the park is 1,11,739 square feet.
Step-by-step explanation:
Since, the area of a triangle is,
[tex]A=\frac{1}{2}\times s_1\times s_2\times sin\theta[/tex]
Where, [tex]s_1[/tex] and [tex]s_2[/tex] are the adjacent sides and [tex]\theta[/tex] is the included angle of these sides,
Here, the two adjacent sides of the park are 533 feet and 525 feet, while, the angle included by these sides is 53°.
That is, [tex]s_1[/tex] = 533 ft, [tex]s_2[/tex] = 525 ft and [tex]\theta[/tex] = 53°,
Hence, the area of the park is,
[tex]A=\frac{1}{2}\times 533\times 525\times sin 53^{\circ}[/tex]
[tex]=\frac{279825\times 0.79863551004}{2}[/tex]
[tex]=\frac{223478.181599}{2}=111739.090799\approx 111739\text{ square ft}[/tex]
Answer:
Step-by-step explanation:
A park in a subdivision has a triangular shape. Two adjacent sides of the park are 533 feet and 525 feet. The angle between the sides is 53°. Find the area of the park to the nearest square foot.
